Regula Falsi Method Or Method of false position

 #Root of x**3-2*x-5 by regula fasli method-problem 2.6 sastry

from math import*

def f(x):

return (x**3-2*x-5)

a=2

b=3

x=(a*f(b)-b*f(a))/(f(b)-f(a))

print ("The successive approximation root is ")

while abs(f(x))>0.0000001:

x=(a*f(b)-b*f(a))/(f(b)-f(a))

print (x)

if f(x)<0:

a=x

elif f(x)>0:

b=x

#Correct root is 2.0945...

Output Screen:

The successive approximation root is 

2.0588235294117645

2.0812636598450225

2.089639210090847

2.0927395743180055

2.0938837084618487

2.09430545112526

2.0944608457664873

2.0945180933857572

2.0945391822940174

2.094546950874257

2.094549812585823

2.0945508667513875

2.094551255072798

2.094551398118127

2.0945514508114953

2.0945514702220622

2.0945514773723